walk

New in version 0.11.0.

Functions

walk

Usage: (walk inner outer form)

walk traverses form, an arbitrary data structure. Applies inner to each element of form, building up a data structure of the same type. Applies outer to the result.

Example:

=> (import [hy.contrib.walk [walk]])
=> (setv a '(a b c d e f))
=> (walk ord identity a)
HyExpression([
  97,
  98,
  99,
  100,
  101,
  102])
=> (walk ord first a)
97

postwalk

Usage: (postwalk f form)

Performs depth-first, post-order traversal of form. Calls f on each sub-form, uses f ‘s return value in place of the original.

=> (import [hy.contrib.walk [postwalk]])
=> (setv trail '([1 2 3] [4 [5 6 [7]]]))
=> (defn walking [x]
...  (print "Walking:" x :sep "\n")
...  x)
=> (postwalk walking trail)
Walking:
1
Walking:
2
Walking:
3
Walking:
HyExpression([
  HyInteger(1),
  HyInteger(2),
  HyInteger(3)])
Walking:
4
Walking:
5
Walking:
6
Walking:
7
Walking:
HyExpression([
  HyInteger(7)])
Walking:
HyExpression([
  HyInteger(5),
  HyInteger(6),
  HyList([
    HyInteger(7)])])
Walking:
HyExpression([
  HyInteger(4),
  HyList([
    HyInteger(5),
    HyInteger(6),
    HyList([
      HyInteger(7)])])])
Walking:
HyExpression([
  HyList([
    HyInteger(1),
    HyInteger(2),
    HyInteger(3)]),
  HyList([
    HyInteger(4),
    HyList([
      HyInteger(5),
      HyInteger(6),
      HyList([
        HyInteger(7)])])])])
HyExpression([
  HyList([
    HyInteger(1),
    HyInteger(2),
    HyInteger(3)]),
  HyList([
    HyInteger(4),
    HyList([
      HyInteger(5),
      HyInteger(6),
      HyList([
        HyInteger(7)])])])])

prewalk

Usage: (prewalk f form)

Performs depth-first, pre-order traversal of form. Calls f on each sub-form, uses f ‘s return value in place of the original.

=> (import [hy.contrib.walk [prewalk]])
=> (setv trail '([1 2 3] [4 [5 6 [7]]]))
=> (defn walking [x]
...  (print "Walking:" x :sep "\n")
...  x)
=> (prewalk walking trail)
Walking:
HyExpression([
  HyList([
    HyInteger(1),
    HyInteger(2),
    HyInteger(3)]),
  HyList([
    HyInteger(4),
    HyList([
      HyInteger(5),
      HyInteger(6),
      HyList([
        HyInteger(7)])])])])
Walking:
HyList([
  HyInteger(1),
  HyInteger(2),
  HyInteger(3)])
Walking:
1
Walking:
2
Walking:
3
Walking:
HyList([
  HyInteger(4),
  HyList([
    HyInteger(5),
    HyInteger(6),
    HyList([
      HyInteger(7)])])])
Walking:
4
Walking:
HyList([
  HyInteger(5),
  HyInteger(6),
  HyList([
    HyInteger(7)])])
Walking:
5
Walking:
6
Walking:
HyList([
  HyInteger(7)])
Walking:
7
HyExpression([
  HyList([
    HyInteger(1),
    HyInteger(2),
    HyInteger(3)]),
  HyList([
    HyInteger(4),
    HyList([
      HyInteger(5),
      HyInteger(6),
      HyList([
        HyInteger(7)])])])])

macroexpand-all

Usage: (macroexpand-all form &optional module-name)

Recursively performs all possible macroexpansions in form, using the require context of module-name. macroexpand-all assumes the calling module’s context if unspecified.

Macros

let

let creates lexically-scoped names for local variables. A let-bound name ceases to refer to that local outside the let form. Arguments in nested functions and bindings in nested let forms can shadow these names.

=> (let [x 5]  ; creates a new local bound to name 'x
...  (print x)
...  (let [x 6]  ; new local and name binding that shadows 'x
...    (print x))
...  (print x))  ; 'x refers to the first local again
5
6
5

Basic assignments (e.g. setv, +=) will update the local variable named by a let binding, when they assign to a let-bound name.

But assignments via import are always hoisted to normal Python scope, and likewise, defclass will assign the class to the Python scope, even if it shares the name of a let binding.

Use importlib.import_module and type (or whatever metaclass) instead, if you must avoid this hoisting.

The let macro takes two parameters: a list defining variables and the body which gets executed. variables is a vector of variable and value pairs.

Like the let* of many other Lisps, let executes the variable assignments one-by-one, in the order written:

.. code-block:: hy

=> (let [x 5 … y (+ x 1)] … (print x y)) 5 6

Unlike them, however, each (let …) form uses only one namespace for all its assignments. Thus, (let [x 1  x (fn [] x)] (x)) returns a function object, not 1 as you might expect.

It is an error to use a let-bound name in a global or nonlocal form.